Where did I go wrong??
The question got cropped off :/ duh! A sphere of mass m rolls without slipping on an inclined plane of inclination theta.Find the linear acceleration of the sphere and the force of friction acting on it.What should be the minimum co-efficient of static friction to support pure rolling... I got 2 answers,:/ both seem legit,but obviously one of them is corrrect..which and why?:/
@Mashy @shubhamsrg !!
@RnR
please batado yaar :/
Hmm. I guess the acceleration would be 5/7gsin(theta)
torque center ke about kyu liya aur point of contact ke about kyu nahi ?
meri marzi hai wo to? jis point ke about calculate kare uski velocity 0 honi chahiye.. aur @RnR u mean a 3rd answer? dafuq,why?,dono galat hai? :/
yesh, accn wahi hoga! B|
??
oye apna solution mat bata :/ maine kya galti kari wo bata >.<
Teri friction to sahi hai 2/5ma. Baaki dekhne de.
yesh, @RnR is right again! friction sahi hai 2/5ma! !!!
:') mereko kuch aata hai.
"I got my mistake,5/7g sin theta aagaya par first wala case kyun galat hai?" ~ DLS :')
Ye mgsin(theta)/6 kahan se aaya? Jab a=5F/2m --> F=2/5ma ?
"I got my mistake,5/7g sin theta aagaya par first wala case kyun galat hai?"
f=mgsin theta/6 kyun nahi hai??
see the first case..kaunsa step galat hai??
Ye aaya kahan se mereko yahi nhi pta lag rha. :/
lol..
kya kahan se aya?!?! kya exactly??
a= gsin(theta) - F yahan se mgsin(theta)/6=a kahan se aaya?
Acha ab mai samjha.. vo isliye nhi hai.. kyunki mgsin(theta) - F= ma hai.. gsin(theta) is not equal to a.
To jo tune 2/5ma=2/5mgsin(theta) likha hai vo galat hai.
Torque=fR Moment of Inertia=2/5MR^2 fR=2/5MR^2 alpha alpha nikaal lo..fir aage deklhlo?
alpha nikaal ke kya krna hai? :/
arre haan wo galat hai!! but see the 1st case..left wala..right kyun dekh raha hai??
merko pata hai answer ka logic sahi hai but left wale me kya galat hai !?
alpha ko a/R nahi likha bus..aage to wahi cheez kari par.. a=R alpha?!
gsin(theta) - F/m =5F/2m iske baad na?
???
do case banaye hai maine? |dw:1364316535604:dw|
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