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Mathematics 15 Online
OpenStudy (anonymous):

Evaluate each expression if x = 14, y = 5, and z = 6. x + (y-2z)

OpenStudy (anonymous):

@Hope_nicole

OpenStudy (anonymous):

Why is it in parenthesis if you're adding

OpenStudy (anonymous):

some equations just put it that way @AngelCriner

OpenStudy (anonymous):

Yea

OpenStudy (anonymous):

plug in all the values given to you.

OpenStudy (anonymous):

Lol I was about to try the problem, but Idk what I'm doing, sorries

OpenStudy (anonymous):

Me Either :/ @AngelCriner

OpenStudy (anonymous):

plug in the values they gave you of x, y, and z into the equation.

OpenStudy (anonymous):

Imma still try anyways.... 14 + 5 - 2(6) ?

OpenStudy (anonymous):

14+ (5-12)

OpenStudy (anonymous):

2(6) ** My Bad

OpenStudy (anonymous):

14+(5-12) is right, now you do the parenthesis first so do 5-12 and then add 14 to it.

OpenStudy (anonymous):

5-12 Is -7 & -7 Plus 14 Is 7

OpenStudy (anonymous):

yupp!

OpenStudy (anonymous):

But 7 Aint One of MY Options -__-

OpenStudy (anonymous):

what are your options and are you sure you copied the right equation?

OpenStudy (anonymous):

Oh Wait never Mind Is .. THANKS :)

OpenStudy (anonymous):

no prob!

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