Question

what is b^2-2b-2 simplified

Answer 1

b(b-2)-2 or (b-1)^2 - 3

Answer 2

\[b^2-2b-2=0\]
\[b_{1,2}=\frac{-(-2)\pm\sqrt{(-2)^2-4(1)(-2)}}{2(1)}\\=\frac{2\pm\sqrt{4+8}}{2}\\=\frac{2\pm\sqrt{12}}{2}\\=\frac{2\pm2\sqrt{3}}{2}\\=1\pm\sqrt{3}\]
\[\Big(b-(1+\sqrt 3)\Big)\Big(b-(1-\sqrt 3)\Big)=0\]


\[b^2-2b-2=\Big(b-(1+\sqrt 3)\Big)\Big(b-(1-\sqrt 3)\Big)\]