Question

can someone help me to find the factor for this
8r^3 - 64t^3

Answer 1

Any ideas?

Answer 2

OpenStudy values the Learning process - not the ‘Give you an answer’ process
Don’t post only answers - guide the asker to a solution.

Answer 3

think about difference of cubes (x^3 - y^3) and that 64 is 4^3 and 8 is 2^3

Answer 4

$$8r^3 - 64t^3$$

Answer 5

$$x^3-y^3=(x-y)(x^2+xy+y^2)$$

Answer 6

I am totally lost

Answer 7

8r^3 = (2r)^3 right? and 64t^3=(4t)^3
so lets call 2r = x
and 4t = y
that would give me x^3 - y^3 for ur initial expression right?
if u plug in skull formula and after change x and y to their originals u'll get the answer