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(√3) cosΘ -2sinΘcosΘ=0 answer: 0º, 45º, 135º, 180º but i got 0º, 45º, 135º, 180º, 360º. Why 360º is rejected?
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Did the problem specify a domain? Perhaps they only want answers in this interval: \[0^{o}\le \theta <360^{o}\]
that was my thought too, but i don't think 360 work
\(\cos(360)=\cos(0)=1\) and so \(\sqrt{3}\cos(360)=\sqrt{3}\)
But then 180 won't work for the same reason
true enough
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\[\cos(x)\left(\sqrt{3}-2\sin(x)\right)=0\] \[\cos(x)=0\] or \[\sin(x)=\frac{\sqrt{3}}{2}\] now that i look, none of these are right
maybe theses are the answers to a different question
|dw:1364478610851:dw|
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