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Geometry 11 Online
OpenStudy (anonymous):

can someone help me with a few questions please?

OpenStudy (andriod09):

questions?

pooja195 (pooja195):

where r they??

OpenStudy (anonymous):

sure what are they?(:

OpenStudy (anonymous):

What is the perimeter of the following polygon?

pooja195 (pooja195):

I think 48 because sides look even and there 3 sides

OpenStudy (anonymous):

ok thanks next 1...

OpenStudy (anonymous):

If the triangles are similar, which ratio shows the relationship of the area of the larger triangle to the area of the smaller triangle?

OpenStudy (andriod09):

Is this off of a test?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

i think its 48, i agree with @pooja195

OpenStudy (anonymous):

ok do you guys know the next one? @pooja195 @callmemaybe16

pooja195 (pooja195):

I think 6:3

OpenStudy (anonymous):

that isnt an option :( @pooja195

OpenStudy (anonymous):

3:2 2:1 3:4 4:1

pooja195 (pooja195):

oops im sorry that wasnt supposed to be here

pooja195 (pooja195):

lets see wat do u think

OpenStudy (anonymous):

i have no idea

OpenStudy (anonymous):

3:4

OpenStudy (anonymous):

thanks! next 1...

OpenStudy (anonymous):

The perimeter of a rectangle is 15 cm, and its dimensions are tripled. What is the perimeter of the larger rectangle?

OpenStudy (andriod09):

^ that's wrong. try working out the problem using ratios

OpenStudy (anonymous):

3*15 = 45

OpenStudy (anonymous):

The length of a rectangle is 6 m, and its width is 14 m. What is the area of half of the rectangle?

OpenStudy (anonymous):

6 x 14 = 84, half of 84 is 42 :)

OpenStudy (andriod09):

callmemaybe, work out the problem using ratios on the one where you answered 3:4.

pooja195 (pooja195):

i agree with @callmemaybe16

OpenStudy (anonymous):

ig2g,(: if u need any more help, tag me!(: ~

OpenStudy (anonymous):

All of the triangles in the figure below are congruent. What is the area of the figure? Note that all measurements are in centimeters. Note that the apothem shown is equal to 3 square root of three.

OpenStudy (anonymous):

if u want, i can help u, when i get back on...just tag me later in it,,..bye..

OpenStudy (anonymous):

thanks! @callmemaybe16

OpenStudy (anonymous):

help! @pooja195

pooja195 (pooja195):

hmm... mot sure

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