Ask your own question, for FREE!
Algebra 22 Online
OpenStudy (anonymous):

HELPPPPPPPPPPPPPPPPPP!!!!! PLEASE ;) What are the focus and directrix of the parabola with equation

OpenStudy (anonymous):

OpenStudy (mertsj):

That is not an equation.

OpenStudy (anonymous):

you have a form of a parabola is y^2 =4px. yours is 1/16 x = 4 *1/64 x. So, your p = 1/64,

OpenStudy (anonymous):

@Mertsj let it go, you know what it is, right? he is , too

OpenStudy (anonymous):

@Mertsj since you here, do your job, please. I am pretty sure you are much more better than me.

OpenStudy (anonymous):

@Hoa these are the answer choices (0, 4); directrix y = −4 focus (4, 0); directrix x = 4 focus (0, 16); directrix y = −16 focus (16, 0); directrix x = 16

OpenStudy (anonymous):

ok, let my check/

OpenStudy (anonymous):

k

OpenStudy (anonymous):

ok, so i stuck . I don't know what is wrong with my stuff. text message to Mertsji . i am terribly sorry

OpenStudy (mertsj):

is your equation y^2=(1/16)x?

OpenStudy (mertsj):

I guess the asker has lost interest in the problem. He is gone.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!