Question

find the extreme values of the function and where they occure. y= x^3-3x^2+6x-8

i got y' = 3x^2-6x+6
x^2-2x+2
(x-1)(x-1)
x = 1

Answer 1

oh wait i wasn't paying attention
\[x^2-2x+2\neq (x-1)^2\]

Answer 2

\[x^2-2x+2\] has no real zeros

Answer 3

because it can't be factored?