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Physics 12 Online
OpenStudy (anonymous):

Kinetic energy of a proton if its velocity is 4E^5m/s (in electron-volts)

OpenStudy (anonymous):

K.E = 1/2 * mv^2

OpenStudy (unklerhaukus):

\[m_p=1.67\times10^{-27}[\text{kg}]\]

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