Question

How do I set up the polar or trig form of -81i ?

Answer 1

the angle is \(270\) or \(\frac{3\pi}{2}\) as you are on the \Ii\) axis

Answer 2

so it is \(81(\cos(\frac{3\pi}{2}+i\sin(\frac{3\pi}{2}))\)

Answer 3

thank you!