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w^2+2w-8=0 solve by factoring
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What are two numbers that multiply to -8 AND add to 2 ?
-2 and 4
Ao now substtute it dat way... Its a quadratic u no...
w^2+2w-8 = w^2 + 4w - 2w -8 = w(w + 4) - 2(w + 4) = (w - 2) * (w + 4). That is factoring by grouping.
(w - 2) * (w + 4) = 0 So, w-2 = 0 or w + 4 = 0 Solve for w @higherlearning
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2 and -4
Correct.
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