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\[\frac{328\times.045}{(54.2)^2}\]
\[\frac{328\times.045}{(54.2)^2}\approx\frac{300\times.05}{50^2}=\frac{300\times1/20}{50^2}=\]
\[\frac{3\times100}{5^2\times2\times1000}=\]
\[=\frac{3}{5^2\times2}\times\frac1{10}\]
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...
@UnkleRhaukus would A be correct?
\[...=\frac3{25\times2}\times\frac1{10}=\frac{3}{50}\times\frac1{10}=\frac35\times\frac1{100}=0.6\times10^{-2}=6\times10^{-3}=A\checkmark\]
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