@terenzreignz picture below.!
Matrices. Just like linear equations only mxn times the work :) Let's get to work. First, get -5A You can do this by multiplying each and every term in A by -5
i was afraid that's how you do it lmao okay, well i think i have it from here. i will tell you what i get when im done.
Fear not the Scalar Multiplication and the Matrix Addition. Fear the Matrix Multiplication O.O Feeeeaaaar
lmfao xDD im good at matrix addition and subtraction. but idk about multiplication.
Feeeaaarrrrr Just to give you an idea, and don't take this too seriously yet, focus on what you have to do... matrix multiplication looks like this \[\Large \left[\begin{matrix}a & b \\ c & d\end{matrix}\right]\left[\begin{matrix}p & q \\ r & s\end{matrix}\right]=\left[\begin{matrix}ap+br & aq+bs \\ cp+dr & cq+ds\end{matrix}\right]\]
And that was just 2x2 matrices.
0.0 im doing it wrong then. i was just multiplying each number by -5
No, this is MATRIX Multiplication. It's not the same as SCALAR multiplication. I told you not to take this seriously yet -.-
ohhhh xD
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|dw:1364562941991:dw|Recheck.
i meant to put -11
Well then, it's correct, with the -11 set.
yayy! okay heres the next problem i have... ill do it and i want you to just check it please
What's X?
i have to do it first.
So yeah, this is just like a linear equation, only four times the stress ;)
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@terenzreignz ...
Getting dizzy, stand by.
Wrong. Redo it :)
how is it wrong???
Simply is :) Please redo your calculations.
okkk
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