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Mathematics 12 Online
OpenStudy (anonymous):

Help with Factoring Polynomials?

OpenStudy (anonymous):

3x2y2 - 75

OpenStudy (anonymous):

any idea?

OpenStudy (anonymous):

This is what I did, I'm not sure if I did it right though...

OpenStudy (anonymous):

Use the equation box please :P

OpenStudy (anonymous):

= 3(x^2y^2 – 25) = 3(xy+5) (xy– 5)

OpenStudy (anonymous):

1. 3x2y2 - 75 = 3(X²Y² – 25) = 3(XY + 5) (XY – 5)

OpenStudy (anonymous):

same so correct

OpenStudy (anonymous):

I also had to do... 2x3 + 54

OpenStudy (anonymous):

\[3x ^{2}y ^{2}-75 = 3(x ^{2}y ^{2}-25) = 3[(xy + 5)*(xy - 5)]\]

OpenStudy (anonymous):

kk how did you do?

OpenStudy (anonymous):

= 2(x^2 + 27) = 2(x + 3)(x² – 3x + 9) ?

OpenStudy (anonymous):

2. 2x3 + 54 = 2(X² + 27) = 2(X + 3)(X² – 3X + 9)

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

more?

OpenStudy (anonymous):

3 more, can you check them for me?

OpenStudy (anonymous):

ofc go ahead i am here for that

OpenStudy (anonymous):

3 rs - 2r - 3s + 2 = r (3s - 2) - 1 (3s – 2) = (r - 1) (3s – 2)

OpenStudy (anonymous):

3rs - 2r - 3s + 2 = r(3s - 2) - 1(3s – 2) = (r - 1)(3s – 2)

OpenStudy (anonymous):

last two?

OpenStudy (anonymous):

Well, I actually didn't do this one because I got stuck /:

OpenStudy (anonymous):

2x2 – 20x + 40

OpenStudy (anonymous):

give me

OpenStudy (anonymous):

can you try? i can wait

OpenStudy (anonymous):

or you want me to show you?

OpenStudy (anonymous):

Can you show it to me because I feel like I don't even know where to start lol

OpenStudy (anonymous):

Divide everything by 2, You have x^2 - 10x + 20 Use quadratic formula now.

OpenStudy (anonymous):

Check again, it's -10x.

OpenStudy (anonymous):

yea true 2x2 – 20x + 40 = 2(x² – 10x + 20) -------- If you are in higher Std. further factors = 2(x² – 10x + 20 + 5 – 5) = 2[(x² – 10x + 25 – 5)] = 2[(x – 5)² – (√5)²] = 2[(x – 5 + √5][(x – 5 – √5]

OpenStudy (anonymous):

thank you dharmaputra he is rigth!

OpenStudy (anonymous):

annetta this is the answer

OpenStudy (anonymous):

Using quadratic formula, the roots would be, -2765 and - 7.235

OpenStudy (anonymous):

Ok, my last one... 21x2 + 31x + 4

OpenStudy (anonymous):

-2.765*

OpenStudy (anonymous):

21x2 + 31x + 4 = 21x² + 28x + 3x + 4 = 7x(3x + 4) + 1(3x + 4) = (7x + 1)(3x + 4)

OpenStudy (anonymous):

So the roots would be -1/7 and -4/3 ;)

OpenStudy (anonymous):

voila ^^

OpenStudy (anonymous):

Lol, @Dharmaputra_993 you're on a roll!

OpenStudy (anonymous):

@Annetta_Martin @nader1 beats me to it every time :P

OpenStudy (anonymous):

lool sorry :Pi just help her many time ^^

OpenStudy (anonymous):

@nader1 I don't mind.

OpenStudy (anonymous):

You guys are awesome, thank you! <3

OpenStudy (anonymous):

^^

OpenStudy (anonymous):

@Annetta_Martin @nader1 did all the work, but no problem!

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