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Simplify the expression (k^1/2)^-9 _____________ (k^4)^1/8
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\[\frac{ k ^{-9/2} }{ k ^{4/8} } = \frac{ k ^{-9/2} }{ k ^{1/2} }=\frac{ (k ^{1/2})^{-9} }{ k ^{1/2} }\]
Thanks Dharmaputra.
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