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simplify (e^x+16e^-x)/(2) = 4....how do u go about simplifying this to natural log form?
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so far i have e^x+16e^-x=8
is this the original problem?
the top one is. i know the answer is 2log2, i'm just trying to figure out the steps in between, i have a final coming up
i know log( base a) b = c and a^c=b ...i just can't figure it out.
are you sure it is -x for the power and why did they not use 2ln2 which is ln4 why use a common log when it should be ln because of base e
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the problem is given in base e and im supposed to re-write it in natural logs
|dw:1364654867462:dw|yes this is correct
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