Question

2) 1^2 + 4^2 + 7^2 + ... + (3n - 2)^2 = n(6n^2-3n-1)/2

Answer 1

What should you do with this expression? Prove it by induction?

Answer 2

yea im having a little difficulty doing that

Answer 3

You should start from the expression you want to get to i. e. \[\frac{ (n+1)(6(n+1)^{2} - 3(n+1) - 1)}{ 2 }\] expand it and arrange the addends in way to get to this expression.

Answer 4

i actually got it