Question

A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches the surface in 9.00 seconds?

Answer 1

g = 1.62 m/s ^{2} on the moon surface.
\[\Delta x = v _{0}t + 1/2 g t ^{2}\]
As the feather is dropped v0t = 0. Therefore \[\Delta x = 1/2 g t ^{2}\]
Are you able to work this out now?