Question

solve for x: log2 (x-3) + log2 (x+1) = 5

Answer 1

I suggest using wolfram alpha, just search it in your browser

Answer 2

thank you!

Answer 3

this is the property: logb(xy) = logbx + logby
you multiply (x-3) & (x+1)

Answer 4

start with
\[\log_2((x-3)(x+1))=5\] and then rewrite in exponential form as
\[(x-3)(x+1)=2^5\] solve the quadratic, check your solutions