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Calculus1 13 Online
OpenStudy (anonymous):

Need quick help? sum_{1}^{n} 4( \frac{ k }{ n }) = 2(n+1) Don't understand how the answer came out. Can someone help me how i got 2(n+1)?

OpenStudy (anonymous):

\[\sum_{1}^{n} 4( \frac{ k }{ n }) = 2(n+1) \]

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