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OpenStudy (anonymous):
Need quick help? sum_{1}^{n} 4( \frac{ k }{ n }) = 2(n+1) Don't understand how the answer came out. Can someone help me how i got 2(n+1)?
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OpenStudy (anonymous):
\[\sum_{1}^{n} 4( \frac{ k }{ n }) = 2(n+1) \]
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