For example, there are balls marked b1, b2, up to b15; i16, i17, up to i30; and so on. Assuming one bingo ball is selected at random, determine the odd against it containing the letter G. Total G balls =15 Total Non-G balls=60 Total number of balls=75 60/75 15/75 60/75*15/75=60/15 60/15=4/1 Odds against it being the G ball =4:1
I"m trying to find the probability of NOT containing the letter G
This is what I have so Far Total G balls =15 Total Non-G balls=60 Total number of balls=75 60/75 15/75 60/75*15/75=60/15 60/15=4/1 Odds against it being the G ball =4:1
Any tips would be very helpful. Thank you
# of G-balls: 15 ----- # of non-G balls: 60
P(non-G) = 60/75 P(G-balls) = 15/75 --- Odds against it being a G-ball = (60/75)/(15/75) = 60/15 = 4:1
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