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-4ln2x=-26 solve each equation or inequality. round to the nearest ten thousandth.
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\[\ln 2x=\frac{13}{2}\]
Now put it in exponential form
Wait, I'm confused because so far I have \[\ln2x ^{-4}=-26\]
Ok. It would be much easier to just divide both sides by -4 but if you must...then \[\ln (2x)^{-4}=-26\]
\[\ln \frac{1}{(2x)^4}=-26\]
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Now put it in exponential form.
I need an answer put to the nearest ten thousandth
Then put it in exponential form.
What is the base?
\[e ^{13}=x ^{-4}\]
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\[e ^{-26}=\frac{1}{(2x)^4}\]
So \[(2x)^4=\frac{1}{e ^{-26}}=e ^{26}\]
Take the 4th root of both sides and divide the answer by 2
|dw:1364695555973:dw|
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