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Find the amount of work done in emptying a cylindrical tank completely filled with kerosene. Assume that the radius of the cylindrical tank is 3 m, height is 6 m, and the density of kerosene is 817.15 kg/m3.
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i don't understand the (6 - h) term inside the integral. If I integrate from 0 -6 i get 138,626.23 but the answer shown is 415,879?
It's the procedure ... you have to understand.
That doesn't help much. Why is the answer exactly 3 times what I get?
Never mind, i got it. i haven't seen that notation in the parentheses before. thanks
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