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OpenStudy (sh3lsh):
I know the answer, but want to know how to solve this. e^(2x)-3e^x+2=0
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OpenStudy (goformit100):
Simply differentiate it....
OpenStudy (sh3lsh):
How so?
OpenStudy (anonymous):
see carefully,its a quadratic equation
OpenStudy (anonymous):
let e^x=t, then the equation becomes |dw:1364751102758:dw| so you have|dw:1364751204203:dw| where ln=natural log
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