Question

for resonance in closed column freq. = (2p+1)*vel/4l . but in class 10 i learned for resonance with a tuning fork say 512 hz this value of frequency should be 512 hz only . so my question if i put p =1,2,3... how to prove that the frequency is remaining same .

Answer 1

some one please comment what ever you feel about my question

Answer 2

i know the length is changing but how to mathematically get it proved that the freq. is remaining constant

Answer 3

come on frnds anybody reply