Question

Find dy/dx

Answer 1

\[y=\int\limits_{2}^{3x^2} \sqrt{1+sint} dt\]

Answer 2

integrate first. then take the derivative

Answer 3

using fundamental theorem of calculus:\[\sqrt{1+\sin(3x^2)} *d/dx(3x^2)=6x*\sqrt{\sin(3x^2)+1} \]

Answer 4

Would you do anything with the 1+sin(3x^2)?