Question

If sin(xy)= x then dy/dx = ?

Answer 1

Well first you have to solve for y. \[\sin(xy)=x \rightarrow y=\frac{ \sin ^{-1}x }{ x }\]Then you derivate that.\[\frac{ d }{ dx }y=\frac{ \frac{ 1 }{ \sqrt{1-x ^{2}} }x+\sin ^{-1}x}{ x ^{2} }\]

Answer 2

So how would you put it in terms of dy/dx ?