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What is the product of -8x^2y and -2xy^3 ? Use the law of exponents to find the product. > Show your work.
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ok if you have \(a^j\), we call a the base and j the exponent . If we multiply two numbers that have the SAME BASE, raised to any exponent, we ADD the exponents. So for example \[a^ja^k=a^{j+k}\]A numerical example would be\[3^2\cdot 3^4=3^{2+4}=3^6\]
so in this case you have \[-8x^2y\cdot -2xy^3\]So you get \[-8\cdot -2 \cdot x^2\cdot x^1\cdot y^1\cdot y^3\]\[=16x^{2+1}y^{3+1}\]
Thank you @richyw for your help!
no worries!and (of course) you would want to write it as \(16x^3y^4\)
Yes, I did do so.
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