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use the shell method to find the volume bounded by y= 2sqrt(x), and y=6 rotated around the y-axis
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Do you know how to get started with this problem? You can start by drawing the graph.
yes i have the graph already i just don't know how to get the answer
Ok, so how far into the problem do you understand it?
^or what part are you having problems with
I think I started off like this \[2\pi \int\limits_{0}^{6}x(2\sqrt{x})dx\]
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but I am not sure
and if its correct I dont know how to continue
Have you drawn the two functions? That's usually a good start.
|dw:1364860231376:dw|
Your integral is almost correct, make sure to check at what point both functions intersect.
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