Question

5 + 3 =
x^3 – y^3 x^2 +xy + y^2

Answer 1

Is this problem\[\frac{5}{x^3-y^3}+\frac{3}{x^2+xy+y^2}=\]

Answer 2

If it is,\[\frac{5}{x^3 – y^3}+\frac{3}{x^2 +xy + y^2}=\frac{5}{(x-y)(x^2 +xy + y^2)}+\frac{3}{x^2 +xy + y^2}\]\[=\frac{5+3x-3y}{x^3-y^3}\]

Answer 3

Yes thank you

Answer 4

No sweat. Do math every day.