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If the radius of a sphere is increasing at the rate of 2 inches per second, how fast, in cubic inches per second, is the volume increasing when the radius is 10 inches? calculus help anyone?
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do you know an equation for this?
nope..
make that \[V=\frac{2}{3}\pi r^3\]
take the derivative , get \[V'=2\pi r^2 r'\]
you are told \(r'=2\) and that \(r=10\) so you can find \(V'\) by substituting the numbers
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