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Solve trig equation over 0 = x < 2pi tan2x + sec2x =1
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x=pi * n where n is any integer so in ur case its 0,pi,2pi
i cant believe i dont remember this stuff..it was last semester D:
Uhmm can you explain how you got that?
@hahd and the solution sheet says 0, pi :(
oops, lol i didnt notice less than sign it hought it was less than=
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are u familiar with double angle identities
sin2x, cos2x, tan2x
yes
k i would write sec2x as 1/cos2x and sub cos 2x and tan2x with their identities
wouldnt it be 2x/cos?
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no 2x is the angle lol
if ur having trouble understanding someething lemme kno, lol i havent used this site for along time so i dont kno how to fully answer so u gotta help me too XD
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