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The perimeter of an rectange is 380, the Length is 90 yd longer than the width, what are the dimensions
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Let W be the width of the rectangle. Then, W + 90 is the length of the rectangle.
A rectangle has 4 sides. Opposite sides are congruent and have the same measure. Perimeter is the sum of the distances around the rectangle.
w+90=380 w=290?
So, W + W + W + 90 + W + 90 = 380
> w+90=380 w=290? No.
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3w+90=390
3w=300
w=100
W + W + W + 90 + W + 90 = 380 4W + 180 = 380
okay according to your problem its 50
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I think your equation was not correct.
the steps i added the w's, then subtracted and divide
If the width is 50, then what is the length?
140
because it says 90 longer
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Correct.
You can check the answers: 50 + 50 + 140 + 140 = 380.
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