Question

dy/dx ln(xy)=xy^2-x

Answer 1

What are you meant to find or solve?

Answer 2

\[\large \frac{dy}{dx} ln(xy)=xy^2-x\]
\[\large \frac{dy}{dx}[lnx+lny]=xy^2-x\]
\[\large \frac{1}{x}=xy^2-x\]
\[\large 1=x^2y^2-x^2\]
\[\large y^2=\frac{x^2+1}{x^2}\]
\[\large y=\pm \frac{\sqrt{x^2+1}}{x}\]

Answer 3

this question can be solved using bernaoulli method