Question

Anyone good with C#?

Answer 1

I am trying to print the fibbancio sequence for n-number of terms.

Need help
---------

int a = 0;
int b = 1;
int c;
Console.Write("please input number of series digits you want to go till:");
c = int.Parse(Console.ReadLine());
int x;
for (int i = 1; i <= (c - 2); i++)
{



x = a + b;
a = b;






}


Console.WriteLine("0,1,{0}", a);

Answer 2

do it like this..
for(int i=0;i<n;i++)
{
a=b;
b=c;
c=a+b;
cout<<c;
}
will do.

Answer 3

That's C++ :/

Answer 4

Moreover we know that the first two terms of the sequence are 0 and 1

Answer 5

man.
int a=0;
int b=1;
for(int i=0;i<n;i++)
{
a=b;
b=c;
c=a+b;
cout<<c;
Console.Write(c);
}

Answer 6

So we can keep them as same.

Answer 7

remove the cout thing use the Console.Write thing instead.

Answer 8

Therfore,We are counting it upto n-2 terms.

Answer 9

both are OOP based,same code.

Answer 10

n-2? no?

Answer 11

Yes i am right.

Answer 12

Because i am putting two terms already which i know can never change which are 0 and 1.

Therefore subtracting these terms from n it comes as n-2

Answer 13

int a=0;
int b=1;
for(int i=0;c<=n;i++)
{
a=b;
b=c;
c=a+b;
Console.Write(c);
}
-------------------------------------------------------------
Please input number of series digits you want to go till
-------------------------------------------------------------
10
-------------------------------------------------------------
0 1 1 2 3 5 8

Answer 14

where are you getting confused?

Answer 15

You will never get my point.

Nevermind.

Answer 16

Confused?

I am not confused at all.

Answer 17

I just want to know how to get the printing done.

Answer 18

Shouldn't you mention that in your question? -_-

Answer 19

Ah!

That was understood.

My Idea is right.

But i am not able to print it.

Answer 20

oh well.
print the first 2 values before the loop?
then display C

Answer 21

like,

Its gonna be like 0,1,1 But then that 1 which is c has to keep changing but it just appears as 0,1,1 < That's it.

It should be like 0,1,1,2,3,5,8,13...

Answer 22

you never reassign the value x = a + b to b, so your program keep calculating a + b while they both stay 1, and you want to print the number as you calculated it, because you don't have access to the calculated numbers after the loop.

ie:
int a = 0;
int b = 1;
int c;
Console.Write("please input number of series digits you want to go till:");
c = int.Parse(Console.ReadLine());
int x;
Console.Write("0 1 "); // Writing the first two terms
for (int i = 1; i <= (c - 2); i++)
{
x = a + b;
a = b;
b = x;
Console.Write("{0} ", x);
}

Answer 23

ahummmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Answer 24

@Meepi I tried to dry run it and got my error and did exactly the same as you did.Thanks anyways.

Answer 25

Are you sure that you rebuild the thing? I've tested it and it works for me :/