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Mathematics 19 Online
OpenStudy (anonymous):

Which equation is correct? isn't it the second one sec x° = opposite ÷ adjacent cosec x° = opposite ÷ adjacent cosec x° = hypotenuse ÷ opposite sec x° = adjacent ÷ hypotenuse

OpenStudy (anonymous):

Cosec =1/sinx Sin x = opp/hyp . , cosec = hyp./opp.

OpenStudy (anonymous):

So it would be the third

OpenStudy (anonymous):

Exactly ! :)

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

yw

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