Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

Solve for x: −3(x + 3) = −3(x + 1) − 5

OpenStudy (anonymous):

the x cancels out of this equation

OpenStudy (anonymous):

So No Solution?

OpenStudy (anonymous):

it's not true then....so yeah

OpenStudy (anonymous):

wait....

OpenStudy (anonymous):

Okay thanks a million

OpenStudy (anonymous):

you're welcome! let us know if you have any other questions :)

OpenStudy (anonymous):

I have one more if thats okay?

OpenStudy (anonymous):

One month, a music site observed that 60% of the people who downloaded songs from its site downloaded Q Sam's latest single. The equation below represents this information, where x represents the total number of people who downloaded songs from the site that month. x = 0.6x + 384 How many people who downloaded songs from the site that month downloaded Q Sam's latest single? 576 240 144 960

OpenStudy (anonymous):

there are two x's in the equation, was that a typo?

OpenStudy (anonymous):

not exactly

OpenStudy (anonymous):

Oh okay

OpenStudy (anonymous):

they would at least have to give you the number of people who downloaded songs from the site in general

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

otherwise you could cancel out the x's...make one side equal 0, then set the 0 equal to y. Are you sure the left hand x is not y?

OpenStudy (anonymous):

I copied it from my test but they probably made a mistake

OpenStudy (anonymous):

signing off, good luck guys!

OpenStudy (anonymous):

well, let's solve the question under the assumption that it's y. If you only have one x and a bunch of numbers, what do you think you could do with them to get your y values?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!