Question

Please Help I have a test tomorrow and I don't understand how to solve this :(
Solve by factoring..
4x^2 − 20 = 5

Answer 1

i forgot about the 4, sorry

Answer 2

\[4x^{2}-25=0\]
use the quadratic equation to solve...
x1=2.5
x2=-2.5

Answer 3

i should shut up, two mistakes
let me try one more time
\[4x^2-25=0\]
\[(2x+5)(2x-5)=0\]

Answer 4

so \(2x+5=0\iff 2x=-5\iff x=-\frac{5}{2}\)

Answer 5

and the other one is
\[2x-5=0\iff 2x=5\iff x=\frac{5}{2}\]

Answer 6

\[x=(-b \pm \sqrt{b ^{2}-4ac})/2a\]

when
a=4
b=0
c=-25

Answer 7

you can also do this
\[4x^2=25\]
\[x^2=\frac{25}{4}\]
\[x=\pm\sqrt{\frac{25}{4}}=\pm\frac{5}{2}\]

Answer 8

Thank you guys