Question

Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary.

A = 50°, b = 30 ft, c = 14 ft

160.87 ft2

420 ft2

134.99 ft2

321.74 ft2

Answer 1

\[Area=\frac{1}{2}bc\sin(A)\] and a calculator

Answer 2

A=\[A=\frac{ 1 }{ 2 } (30)(14) Sin(50)\]
\[A=\frac{ 1 }{ 2 } 420 Sin(50)\]
\[A=\frac{ 1 }{ 2 } 420 (0.78)\]
\[A=\frac{ 1 }{ 2 } (327.6)\]
\[A=163.8\]
is this right?

Answer 3

thank you! @satellite73