Question

Where does the graph of y = sin x from x = 0 to x = 2pi start?

Answer 1

when x = 0, y is..

y = sin(x)

y = sin(0)

y = 0

Answer 2

So the point (0,0) is on the graph of y = sin(x)

Answer 3

When x = 2pi, y is..

y = sin(x)

y = sin(2pi)

y = 0

which means that the point (2pi, 0) is also a point on y = sin(x)