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I need some help graphing the parabola !!!!!
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do you have a graphing calculator?
nope but heres the parabola
y=(x+3)^2-4
the vertext is (-3,-4) right?
i just need to graph it
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thats hard :(
i have homework for graphing a parabola. My teachers gives us simple ones.
do you have the standard form formula for the parabola handy?
nope
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the "vertex" form is pretty much what you have
wait whats my vertex points? is it (-3,-4) or (3,-4)?
the coefficient for the squred binomial is "1", thus a positive number, thus it opens "upward" the vertex is the "h,k" from the vertex formula
i know but what is my vertex points?!?!?!
the vertex is the vertex :), the spot from where the parabola stems up/down
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So its (-3,-4) or (3,-4)?
(x-(-3)^2, so -3,-4
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