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find the sum of the first eight terms of the AP -1,2,5,8
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-1+2+5+8+(8+3)+(8+3+3)+(8+3+3+3)+(8+3+3+3+3)=SOMETHING USE CALCULATORZZZ
sum of n terms of an AP is given by Sn = (n/2)[2a + (n-1)d] where n = no. of terms, a = first term and d = common difference
Or you could just add all those 3's
yes that would give the correct answer its ok for a small number of terms but heavy work say for 502 terms - then you use the formula!
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