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OpenStudy (anonymous):
What is the derivative of 1-1/x? My answer was 1/x^2. Is that correct?
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OpenStudy (anonymous):
absolutely
OpenStudy (anonymous):
great! thanks :)
OpenStudy (anonymous):
d/dx[1]-d/dx[1/x] --> 0-d/dx[x^-1] --> By Chain Rule --> -1*-1*x^-2=1/x^2
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