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A television set is 36 inches wide and has a diagonal length of 42 inches. To the nearest inch, how tall is the set?
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\[\sqrt{42^2-36^2}\] and a calculator
it is like the last one \[a^2+36^2=42^2\] solve for \(a^2\) then solve for \(a\) or do it in one step as i wrote above
468
yes, then take the square root
21?
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\(21.63\) to the nearest 100th
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