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Mathematics 19 Online
OpenStudy (anonymous):

Solve for x. Please Help! sin2x−1/cos(π/2−x)+1=3√/2−1

OpenStudy (aravindg):

cos(π/2−x) is same as sin x

OpenStudy (anonymous):

I have that part down ^_^

OpenStudy (aravindg):

is the qn (sin 2x-1)/(cos π/2−x) +1 =3√/2−1

OpenStudy (aravindg):

?

OpenStudy (anonymous):

its sin squared

OpenStudy (anonymous):

my bad :P

OpenStudy (aravindg):

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