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( cos theta - cot theta ) / 1- sin theta = - cot theta prove the identity.. i'm having troubling making the LS equal the RS
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write cot theta= cos theta/ sin theta in LS what you get ?
then you can factor out cos theta from numerator.
what? i don't understand
did you know this : cot theta= cos theta/ sin theta
yes i know that
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then use that in LS
( cos theta - cot theta ) / (1- sin theta) = ( cos theta - cos theta/ sin theta ) / (1- sin theta) got his ? now factor out cos theta from numerator, = cos theta (1-1/ sin theta ) / (1- sin theta)
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