Question

use algebra to solve each equation over the doman 0< x < 2pi
give roots to nearest hundredth when necessary
cos x + root 3 sinx = 0

Answer 1

u are preettyy u dont need math

Answer 2

\[\large \sqrt 3 sinx = -\cos x\] divide both sides by cosx so sinx becomes cosx
\[\large \sqrt 3 \tan x = -1\] now divide both sides by sqrt3 and you'll have\[\large \tan x = \frac{ -1 }{\sqrt3 }\]

Answer 3

***sinx becomes tanx

Answer 4

oh okay thank you! i remember it now! thanks