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Mathematics 16 Online
OpenStudy (anonymous):

e^2x=7 Help..

OpenStudy (anonymous):

\[e^{2x}=7 \rightarrow \ln(e^{2x})=\ln7\]\[2x=\ln(7) \rightarrow x=\frac{ \ln7 }{ 2 }\]So remember, \[\ln(e^x)=x\]

OpenStudy (anonymous):

final answer is ln/2?

OpenStudy (anonymous):

\[\frac{ \ln7 }{ 2 }\]

OpenStudy (anonymous):

ok thank you i understand

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