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Graph question. Graph: 4x^2 How is this done?
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good qUestion. maybe yoU should first determine its vertex, then evalUate the fUnction at some points near the vertex, and yoU will get a general idea of what the cUrve should be. yoU can use the vertex formUla to get the vertex, bUt this seems too simple to have to involve complex looking formUlas. so i will just tell yoU that the vertex of this fUnction is at the point (0,0)
use a table
|dw:1365078220236:dw|
thats not a graph, thats a sketch :)
Thanks a bunch I understood everything very well :)
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yes I know its a sketch but based on my table
yw
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