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OpenStudy (anonymous):
Factor by grouping. b^3-2+5ab^3-10a
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Directrix (directrix):
b^3-2+5ab^3-10a = 5ab^3 + b^3 - 10a - 2 = b^3 ( 5a + 1) - 2(5a +1) = ? Note that the common factor is (5a + 1)
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